I need to prove Lim X --> (-2) of (3x)/(3x+2) = 3/2 Using the Epsilon - Delta definition of limit. ( | are my absolute value signs, not a form of parentheses )

For preliminary i have: if, 0<|x+2|< (delta), then, | { (3x)/(3x+2) } - { 3/2 } | < (epsilon)

I believe I need to then figure that | { (3x) (2) / (3x+2) (2) } - { (3) (3x+2) / (2) (3x+2) } | < (epsilon)

So I have | { (6x)/(3x+2)(2) } - { (9x+6)/(3x+2)(2) } | < (epsilon)

Then I have | { (-3x-6)/(3x+2)(2) } | < (epsilon)

If that part is correct so far, I have no idea where to go next.