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Math Help - Side of a square is 12 inches with a possible error of 1/64th of an inch?

  1. #1
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    Side of a square is 12 inches with a possible error of 1/64th of an inch?

    1. Use differentials to approximate the possible propagated error in computing the area of the square.

    2. Find the percent error to the nearest 100th of a percent.

    I think I got the first one, A' = 3/8th in^2 but I have no idea how to get the second?
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  2. #2
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    Re: Side of a square is 12 inches with a possible error of 1/64th of an inch?

    The area of a square of side length x is, of course, A= x^2. The differential is dA= 2x dx so if x= 12 inches and dx= 1/64 inch, dA= 2(12)(1/64)= 3/8 square inch as you say.

    The "relative error" would be \frac{dA}{A} and the "percent error" is that converted to a percent.
    Last edited by HallsofIvy; October 8th 2012 at 03:40 PM.
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