The area of a square of side length x is, of course, . The differential is so if x= 12 inches and dx= 1/64 inch, square inch as you say.
The "relative error" would be and the "percent error" is that converted to a percent.
1. Use differentials to approximate the possible propagated error in computing the area of the square.
2. Find the percent error to the nearest 100th of a percent.
I think I got the first one, A' = 3/8th in^2 but I have no idea how to get the second?
The area of a square of side length x is, of course, . The differential is so if x= 12 inches and dx= 1/64 inch, square inch as you say.
The "relative error" would be and the "percent error" is that converted to a percent.