# Thread: one to one function

1. ## one to one function

i dont understand how to prove it

if f is a one-to-one fuction, prove that g(x) = -f(x) is also one-to-one

can you show the steps

thanks alot

2. ## Re: one to one function

Originally Posted by ubhutto
i dont understand how to prove it
if f is a one-to-one fuction, prove that g(x) = -f(x) is also one-to-one
can you show the steps
The function $f$ is one-to-one if and only if $f(x) = f(y) \Rightarrow \;x = y\text{ or }x\ne y \Rightarrow \;f(x) \ne f(y)$

No I will not do this problem for you. That is yours to do.
Just apply the above to $g(x)~.$

3. ## Re: one to one function

lol i did not ask you to do the problem for me i asked you to explain it to me

4. ## Re: one to one function

Originally Posted by ubhutto
lol i did not ask you to do the problem for me i asked you to explain it to me
What do you think "can you show the steps" means if not 'do it for me'?

Show that if $g(x)=g(y)$ then $x=y$.

5. ## Re: one to one function

"can you show the steps" means that i am trying to understand how to do it for future tests and stop being ignorant, if you don't want to help properly then don't.

6. ## Re: one to one function

and thanks 'alot' for your help, next time please don't help me because apparently you cannot explain properly