Usually I get that one problem a night that I just get completely locked up on and was hoping for an explanation on where I am going wrong. As always thanks for your help, ya'll have been a life saver. Problem below
s= Sqrt. (t^2 - cot*t + 2)^3 Find ds
so I am looking for the differential right? Since its a square root problem I believe I sould be taking diff and putting it in s'= Sqrt[(t^2- cot*t + 2)^3] '
That would go to Sqrt [(t^2 - cot*t + 2)^3'] * dt. Then my algerbra is kicking my butt. Why cant I pull out a (t^2-cot*t + 2)'Sqrt(t^2-cot*t+2)'(dt). then take thir deriv. This stuff kills me,
We just learned this material today, last week we did stuff like dy/dx and d/dx and this says just use dy. Isn't that different than derivatives. I have been wrong a lot but this says differentials. So find ds. s=Sqrt(t^2 - cot(t) + 2)(dx) and then break it down?? I dont understand what I should do to break it down. If I use the chain rule does the Sqrt act as the outside and the (T^2 - cot(t) + 2)(dx) act as the inside?
If you dont mind me asking where does the csc^2t come into play. I understand the 3/2(t^2 - cot t + 2)^1/2 using the product rule and. Also this is Algerbra but to pul it out of the sqrt you raised it to 3/2, well it was raised to 3 but then you raised it by 2? in order to get the 3/2?