Find the derivative of sqrt x = 5 x sqrt y
Answer in the back of the book doesnt make sense to me. d/dx = 1/25
HELPPP!!!!
So it's $\displaystyle \displaystyle \begin{align*} \sqrt{x} = 5\sqrt{y} \end{align*}$. Solving for y gives
$\displaystyle \displaystyle \begin{align*} \sqrt{y} &= \frac{1}{5}\sqrt{x} \\ y &= \frac{1}{25} x \\ \frac{dy}{dx} &= \frac{1}{25} \end{align*}$