Just started derivatives in Math 262 and we are learning the chain rule.
Then I get this:
f(x) = 2x + (2x + (2x +1)^3)^3
Her is what I'm attempting...
2x + 3(2x + 3(2x + 1)^2)^2
Is this even close?
Thanks for any help you might have.
Just started derivatives in Math 262 and we are learning the chain rule.
Then I get this:
f(x) = 2x + (2x + (2x +1)^3)^3
Her is what I'm attempting...
2x + 3(2x + 3(2x + 1)^2)^2
Is this even close?
Thanks for any help you might have.
First of all, the derivative of a sum is equal to the sum of the derivatives. So the derivative of the first 2x is 2. The hard part will be evaluating the derivative of . It's a composition of functions, so the chain rule will need to be used. I always use Leibnitz notation for the chain rule, since it is easier. In this case you will need to do .
So first, if we have , then we let . Then .
As for finding , we notice that . Can you use the Chain Rule to evaluate this final derivative?