Hi,
Would anyone be able to tell me how I'd go about obtaining this answer? Here's what I've done so far.
-2(x) + b => -2(2) + b => -4 + b (from the left side)
-24/x-b => -24/(2)-b (from the right side)
the part/step I don't understand is when you add them together and come out with . . .
(-4+b)(2-b) = -24 ??? How do you come up with this?
I know the next step is multiply out and move -24 to the left so that you set it to = 0.
-8+4b+2b-b^{2 }=-24
-(b^{2}-6b+8)=-24
b^{2}-6b+8=24
b^{2}-6b-16 = 0
(b-8)(b+2) = 0
So the answer to this problem is b=8 (because it has a greater absolute value than 2)
Hope this isn't confusing to anyone reading this. Any help would be greatly appreciated! Thanks, Ana
Here's the problem
There are exactly two values for b which make f (x) a continuous function at x = 2. The one with the greater absolute value is b=?
You don't "add them together"- especially when talking about mathematics don't use the term "add" to mean just combing two things!
What you mean is "in order to be continuous those two one sided limits must be the same so -4+ b= -24/(2- b).
Multiply by both sides by 2- b.(-4+b)(2-b) = -24 ??? How do you come up with this?
I know the next step is multiply out and move -24 to the left so that you set it to = 0.
-8+4b+2b-b^{2 }=-24
-(b^{2}-6b+8)=-24
b^{2}-6b+8=24
b^{2}-6b-16 = 0
(b-8)(b+2) = 0
So the answer to this problem is b=8 (because it has a greater absolute value than 2)
Hope this isn't confusing to anyone reading this. Any help would be greatly appreciated! Thanks, Ana
Here's the problem
There are exactly two values for b which make f (x) a continuous function at x = 2. The one with the greater absolute value is b=?