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Math Help - Partial derivative-need yr urgent help.

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    Question Partial derivative-need yr urgent help.

    partial/partial z = tan^(-1) (z/x) .

    Thank you very much.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by kittycat View Post
    partial/partial z = tan^(-1) (z/x) .

    Thank you very much.
    recall that \frac d{dx} \arctan u = \frac {u'}{1 + u^2} where u is a function of x

    we are taking the derivative with respect to z, so we treat x as if it was a constant.

    Let f(x,y,z) = \tan^{-1} \left( \frac zx \right)

    \Rightarrow \frac {\partial f}{\partial z} = \frac 1{1 + \left( \frac zx \right)^2} \cdot \frac 1x

    and simplify
    Last edited by Jhevon; October 13th 2007 at 05:09 PM.
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