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Math Help - Word prob.

  1. #1
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    Word prob.

    A particle in a magnetic field travels in a straight line. The force (in Newtons) acting upon it is given by the function
    F(s) = square root of (s) s^2, where s = f(t), the position of the particle in meters, changes with time t. At what rate is the force changing with respect to time at a time T for which the particle is at position s = 1 and has velocity 4 m/s.

    Please explain this prob and how to do it!

    Last edited by kwivo; October 12th 2007 at 01:56 PM.
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  2. #2
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    Quote Originally Posted by kwivo View Post
    A particle in a magnetic field travels in a straight line. The force (in Newtons) acting upon it is given by the function
    F(s) = pss2, where s = f(t), the position of the particle in meters, changes with time t. At what rate is the force changing with respect to time at a time T for which the particle is at position s = 1 and has velocity 4 m/s.

    Please explain this prob and how to do it!

    Is that
    F(s) = p*s -s^2 ?

    s = f(t), okay, but what is p?
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  3. #3
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    Sorry, I fixed it.
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  4. #4
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    Quote Originally Posted by kwivo View Post
    A particle in a magnetic field travels in a straight line. The force (in Newtons) acting upon it is given by the function
    F(s) = square root of (s) s^2, where s = f(t), the position of the particle in meters, changes with time t. At what rate is the force changing with respect to time at a time T for which the particle is at position s = 1 and has velocity 4 m/s.

    Please explain this prob and how to do it!

    F(s) = \sqrt{s} - s^2
    where s is a function of t.

    What is
    \frac{dF}{dt}?

    Looks like a chain rule problem to me.

    For example, the first term:
    \frac{d}{dt}\sqrt{s} = \frac{1}{2\sqrt{s}} \cdot \frac{ds}{dt}

    You do the rest.

    -Dan
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