P(c)=-c^2+110c-2400

I need to find the inverse function.

Here's what I have done:

P=-c^2+110c-2400

P+2400=-c^2+110c

P+2400=-c(c-110)

-P-2400=c(c-110)

I know I need to solve for c, but I'm not sure what to do next...

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- Oct 2nd 2012, 05:57 PMlovesmathInverse Function
P(c)=-c^2+110c-2400

I need to find the inverse function.

Here's what I have done:

P=-c^2+110c-2400

P+2400=-c^2+110c

P+2400=-c(c-110)

-P-2400=c(c-110)

I know I need to solve for c, but I'm not sure what to do next... - Oct 2nd 2012, 06:25 PMrichard1234Re: Inverse Function
Start with your first step. Solve for c via the quadratic formula (or factoring if it's possible).

I don't think you'll end up with an inverse function though...P(c) is not bijective. - Oct 2nd 2012, 06:30 PMlovesmathRe: Inverse Function
The two values I got for c were 30 and 80. P(c) represents the daily profit earned as related to the number of cases, c, produced and sold. I have to find a function that gives the number of cases based on the profit desired. Wouldn't that be the inverse function?

- Oct 3rd 2012, 07:32 AMhollywoodRe: Inverse Function
You need to subtract P from both sides first:

0=-c^2+110c-2400-P

Now you can do the quadratic equation with a=-1, b=110, and c=-2400-P (that's c in the quadratic equation, not c the number of cases).

What richard1234 is saying is that when you write out the quadratic equation, you get two solutions (because of the + or -), and you can't have a function with two outputs for the same input. You need more information to figure out which is correct, + or -.

Sometimes in problems like this, the "-" solution ends up being physically impossible - like the number of cases being negative. I don't think that happens in your problem, though.

- Hollywood - Oct 3rd 2012, 08:19 AMHallsofIvyRe: Inverse Function
Technically, since that function is not "one-to-one", it does not

**have**an inverse. That's why you get the "$\displaystyle \pm$" when you solve using the quadratic formula.