i got one more limit problem that i cannot figure out

(x^2 sin x) / (1 - cos^2x) x is 0

how do i prove this

PS i got to the part (x^2 / sinx)

but i dont know how to convert it into sin(x) / (x)

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- Oct 1st 2012, 05:49 PMubhuttolimits help part 2
i got one more limit problem that i cannot figure out

(x^2 sin x) / (1 - cos^2x) x is 0

how do i prove this

PS i got to the part (x^2 / sinx)

but i dont know how to convert it into sin(x) / (x) - Oct 1st 2012, 05:57 PMProve ItRe: limits help part 2
Write it as $\displaystyle \displaystyle \begin{align*} x \cdot \frac{x}{\sin{x}} \end{align*}$. Since $\displaystyle \displaystyle \begin{align*} \lim_{x \to 0} \frac{\sin{x}}{x} = 1 \end{align*}$, so does $\displaystyle \displaystyle \begin{align*} \lim_{x \to 0}\frac{x}{\sin{x}} \end{align*}$. The reason is that for very small values of x, $\displaystyle \displaystyle \begin{align*} \sin{x} \approx x \end{align*}$.