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i don't know how to prove the following limits
limit of ( 1 - cos x) / x^2 when x is +infinity
limit of (tan4x) / 6 when x is 0
limit of (sin x^2) / x
in the first equation i got to the point of multiplying by the reciprocal but i don't know what to do next
in the second equation i converted tan to sin/cos but i dont know where to go from there
In the first,Quote:
Originally Posted by ubhutto
is bounded between 0 and 2, and the denominator goes to
, which makes the fraction go to 0.
For the second, surely you can just substitute in x = 0.
For the third, what is the value of x going to?
it is going to 0
Well multiply top and bottom by x to give
Can you go from there?
i dont understand what to do with the sinx^2 / x^2 , how do i simplify it, if you can help me with that part ill be able to do the rest of the problems i have
You should know thatQuote:
Originally Posted by ubhutto
. Here your
just happens to be
.