I am working on a double integral, and I am now stuck on this integral.

exp(x^2)*(x^2-1)/x^3

Wolfram returned this as an answer:

exp(x^2)/2x

Any help or suggestions will be appreciated!

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- Oct 1st 2012, 05:33 PMdnftpIntegration of exp(x^2)*(x^2-1)/x^3
I am working on a double integral, and I am now stuck on this integral.

exp(x^2)*(x^2-1)/x^3

Wolfram returned this as an answer:

exp(x^2)/2x

Any help or suggestions will be appreciated! - Oct 1st 2012, 06:17 PMHallsofIvyRe: Integration of exp(x^2)*(x^2-1)/x^3
Multiply both numerator and denominator by x to make the integral

and use the substitution so that , . - Oct 5th 2012, 05:17 PMdnftpRe: Integration of exp(x^2)*(x^2-1)/x^3
Thanks!

I know the answer is exp(x)/2x, becuase I can confirm it using the quotient rule for differentiation, but could someone please explain how to show the integration process? - Oct 5th 2012, 05:57 PMProve ItRe: Integration of exp(x^2)*(x^2-1)/x^3
- Oct 7th 2012, 09:19 PMdnftpRe: Integration of exp(x^2)*(x^2-1)/x^3
I realised that I had wrote the equation wrong...it should be

using the substitution suggested I got, = .

Substituting back to x, . The limits on the integration were from 0 to 2.

However, when I do this on wolfram, I get,

I can't see what I am doing wrong.