Find an equation of the tangent line to the graph of f at the indicated point

f(x)=x^{2}+1

(2, 5)

This is what I did:

First step - lim(x+△x)△x->0 .........................△x^{2}+1-(x+△x)^2)

Plugged in 0 to every △x, which turns out to be 1/0, which is undefined

Second step -(x+△x)(x+△x)+1-(x+△x)(x+△x)

....................................△x

Turns into x....................................△x^{2}+2△x+△x^{2}+1-x^{2}-2△x-△x^{2 }

I got lost here, I think I messed up on the 2nd parenthesis, because I thought I should have turned everything negative since there was a minus sign.

But then it cancels everything else except the +1

Can someone help me from here?

Thanks