does (x-2) / (2x^2 +3X - 5) have any horizontal asymptote PS i think its none.
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What do you find when you evaluate: $\displaystyle \lim_{x\to\pm\infty}\frac{x-2}{2x^2+3x-5}$ ?
limit of positive infinity is 0 and the limit of negative infinity is 0
Yes, so that means you have a horizontal asymptote of $\displaystyle y=0$, i.e., the $\displaystyle x$-axis.
thanks and if the limit of lets say f(x) is infinity does that mean that there is no horizontal asymptote.
Right. In this case there could be an oblique asymptote, but not a horizontal one.
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