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Math Help - Limits help please

  1. #1
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    Limits help please

    Lim (3x^3 +3x^2) / (x - 6x^2)
    as x approaches negative infinity

    is the answer positive infinity, if not then can you explain
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  2. #2
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    Re: Limits help please

    Quote Originally Posted by ubhutto View Post
    Lim (3x^3 +3x^2) / (x - 6x^2)
    as x approaches negative infinity

    is the answer positive infinity, if not then can you explain
    Divide through by x^2 to get \frac{3x+3}{\frac{1}{x}-6}.

    Now as x\to-\infty it should clear we get positive numbers.
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