Lim (3x^3 +3x^2) / (x - 6x^2) as x approaches negative infinity is the answer positive infinity, if not then can you explain
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Originally Posted by ubhutto Lim (3x^3 +3x^2) / (x - 6x^2) as x approaches negative infinity is the answer positive infinity, if not then can you explain Divide through by $\displaystyle x^2$ to get $\displaystyle \frac{3x+3}{\frac{1}{x}-6}$. Now as $\displaystyle x\to-\infty$ it should clear we get positive numbers.
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