How do I find the inverse of this function? y = ln(x + 8)
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Originally Posted by Oldspice1212 How do I find the inverse of this function? y = ln(x + 8) Exchange the x and y to get $\displaystyle x=\ln(y+8)$ and now solve for y. This will be the inverse function.
So x would = e^y+e^8?
Originally Posted by Oldspice1212 So x would = e^y+e^8? Not quite. You are correct that the inverse of the natural log is the exponential base e, but be careful the first step should be $\displaystyle e^x=e^{\ln(y+8)}$ Can you finish from here?
Oh right! Thanks, I'll get back to you with my answer :P
Uh I got y = e^x-8
That is correct.
Sweet! Thanks for the hint, I can't believe I forgot that!
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