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Math Help - Maximisation differentiation problem

  1. #1
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    Maximisation differentiation problem

    I need help with this differentiation. I don't think the answers I'm getting are correct. I'm not sure if I'm differentiating it correctly. For the equation and my working go the link below;

    http://i1325.photobucket.com/albums/...ps2da17003.jpg
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  2. #2
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    Re: Maximisation differentiation problem

    Hey daveydave.

    I've looked at what you've posted and it looks correct to me with how you've differentiated and collected terms. I'm assuming the Rj's and the rest of them are all not related in any way to the Ri's.
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  3. #3
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    Re: Maximisation differentiation problem

    I should expain that Ri is firm i's investment and Rj is the other firm's investment. The ki times square root of Ri is the probability that firm i will be successful and kj times square root of Rj is the probability firm j will be successful. Does that make any difference then?
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  4. #4
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    Re: Maximisation differentiation problem

    Are the investments correlated or dependent in any way (potentially or not and under what conditions)?
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  5. #5
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    Re: Maximisation differentiation problem

    Its two competing firms determining how much to invest in R&D. So Ri and Rj is how much the two firms invest in R&D and ki times square root of Ri is the probability of firm having a successful innovation come from R&D so the probability of success is dependent on the level of investment Ri. Not sure if dependence in that direction makes a difference.
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  6. #6
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    Re: Maximisation differentiation problem

    The reason I ask is that if there is any dependency between the two, then your answer will need to involve some extra stuff.

    If Rj = f(Ri) then differentiating with respect to Ri will have a huge effect and will be completely different from your answer since you can't treat it as a constant.
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  7. #7
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    Re: Maximisation differentiation problem

    Oh ok, I get what you mean now. No, they're independent of each. Thank you so much for your help.
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