Yes, that's right- and .

Yes, for a, b, and c. Is d or ? The first does not exist. The second is -3.60. Suppose lim x->4 f(x)=0 and lim x->4 g(x)=3. Find

a. lim x->4 (g(x)+3) b. lim x->4 xf(x)

c. lim x->4 g^2(x) d. lim x->4 g(x)/f(x)-1

I got 6 for a, 0 for b, 9 for c and -3 for d

Yes, these are all pretty direct applications of the "limit theorems".61. Suppose lim x->b f(x)=7 and lim x->b g(x)=-3. Find

a. lim x->b (f(x)+g(x)) b. lim ->b f(x) * g(x)

c. lim x->b 4g(x) d. lim x->b f(x)/g(x)

I got 4 for a, -21 for b, -12 for c and -7/3 for d

Yes.62. Suppose lim x->-2 p(x)=4, lim x->-2 r(x)=0, and lim x->-2 s(x)=-3. Find

a. lim x->-2 (p(x)+r(x)+s(x)) b. lim x->-2 p(x)*r(x)*s(x)

i got 1 for a and 0 for b

You mean x->2, not -2. You are given no information about what happens at x=-2.__________________________________________________ _____________

also 45. let f(x)={a-x^2 if x<2

x^2+5x-3 if x is greater than or equal to 2

For what values of a does lim x->-2 f(x) exist

The "limit from below" is . The "limit from above" is . The limit, itself, exists if and only if those two one-sided limits are the same so we must have a- 4= 11 which does, in fact, give a= 15.i got 15 but im not sure if thats right

Well done!