May I in the following cases:
1. lim x=>a(2x2+3x+1)/x2=2
2. lim x=>a(-2x+(2x2+3x+1)/x)=3
a is infinity.
simply first divide by the denominator and then let x goes to infinity or, am I suppose first to take x out of the numerator then cancel the x(both at the numerator and denominator ) and just then let the x goes to infinity?
Thanks in advance...