If then choose thus we have .
This is because and in either case
Hi Everyone,
I'm new to the forums, but this place sounds awesome. I have a group assignment due tomorrow and we've gotten all of the problems except this last one. Let me know if anyone has any input on it -- it would be greatly appreciated
f(x) = 0 if x is rational
x if x is irrational
With epsilon = .1, find a delta that makes plausible that f is continuous at 0.
Is this even possible? Because as you get closer and closer to x (0) there will always be at least one rational and at least one irrational number in the interval? Thanks so much for your help!!!
Jason