1. ## Limits

Hey guys so I have no idea how to solve limits while looking at a graph, here is the image...

lim
t 0
g(t)

lim
t 0+
g(t)

lim
t 0
g(t)

lim
t 2
g(t)

lim
t 2+
g(t)

lim
t 2
g(t)

g(2)

lim
t 4
g(t)

2. ## Re: Limits

Originally Posted by Oldspice1212

lim
t 0
g(t)

lim
t 0+
g(t)

lim
t 0
g(t)

lim
t 2
g(t)

lim
t 2+
g(t)

lim
t 2
g(t)

g(2)

lim
t 4
g(t)

The answer to the first is $-1$.

The answer to the second is $-2$.

You figure out why. Then do the others and report the answers you get.

3. ## Re: Limits

So for the third one it would be 2 since from the right it goes towards 2 and from left closest is to the 2?

fourth -2?
fifth 1
sixth 2
7th no idea
8th - 3?

4. ## Re: Limits

Hello, Oldspice1212!

Here's part of the solution . . .

I have no idea how to solve limits while looking at a graph.
Do you understand "from the left" and "from the right"?
You just trace it with your finger.
Code:
          |
4+                  *
|                 *
3+               ♥
*    |             *
2+       o    *
|      *    *
*  1+     * ♥  *
|    *    *
- -*- + - * - o - + - + - -
* |  *1   2   3   4
-1♥ *
|*-
-2o
|
$(1)\;\lim_{t\to0^-}g(t)$
As $t$ approahes 0 from the left, $g(x)$ approaches $\text{-}1.$
Hence: . $\lim_{t\to0^-}g(t) \:=\:\text{-}1$

$(2)\;\lim_{t\to0^+}g(t)$
As $t$ approaches 0 from the right, $g(t)$ approaches $\text{-}2.$
Hence: . $\lim_{t\to0^+}g(t) \:=\:\text{-}2$

$(3)\;\lim_{t\to0}g(t)$
Does not exist.

$(4)\;\lim_{t\to2^-}g(t)$
As $t$ approaches 2 from the left, $g(t)$ approaches $2.$
Hence: . $\lim_{t\to2^-}g(t) \:=\:2$

$(5)\;\lim_{t\to2^+}g(t)$
As $t$ approaches 2 from the right, $g(t)$ approaches 0.
Hence: . $\lim_{t\to2^+}g(t) \:=\:0$

$(6)\;\lim_{t\to2}g(t)$
Does not exist.

$(7)\;g(2)$
$g(2) \:=\: 1$

5. ## Re: Limits

Oh wow thank you so much!! The explanations on approaching helped a ton.

6. ## Re: Limits

Quick question for lim g(t)
t - 4

would this = 0 or DNE?