# find the derivative of this function

• Sep 19th 2012, 10:07 PM
arsenal12345
find the derivative of this function
how do i do this

find the derivative of this funtion.
y= ln (ln(tanx))

derive the following properties of log x:
a

how do i do this ?

log U/v = log u-log v
a a a

(the a's are the littlle number/letter at the bottom of log)
• Sep 19th 2012, 10:11 PM
Prove It
Re: find the derivative of this function
Quote:

Originally Posted by arsenal12345
how do i do this

find the derivative of this funtion.
y= ln (ln(tanx))

derive the following properties of log x:
a

how do i do this ?

log U/v = log u-log v
a a a

(the a's are the littlle number/letter at the bottom of log)

You should use the chain rule. In this case, since you have a composition of another composition, you'll need to use the chain rule twice. So

\displaystyle \begin{align*} \frac{dy}{dx} = \frac{dy}{du} \, \frac{du}{dv} \, \frac{dv}{dx} \end{align*}

where \displaystyle \begin{align*} v = \tan{x} , u = \ln{v} \end{align*} and \displaystyle \begin{align*} y = \ln{u} \end{align*}.
• Sep 19th 2012, 10:46 PM
arsenal12345
Re: find the derivative of this function
Quote:

Originally Posted by Prove It
You should use the chain rule. In this case, since you have a composition of another composition, you'll need to use the chain rule twice. So

\displaystyle \begin{align*} \frac{dy}{dx} = \frac{dy}{du} \, \frac{du}{dv} \, \frac{dv}{dx} \end{align*}

where \displaystyle \begin{align*} v = \tan{x} , u = \ln{v} \end{align*} and \displaystyle \begin{align*} y = \ln{u} \end{align*}.

what about the question below that ?
• Sep 20th 2012, 01:50 AM
Prove It
Re: find the derivative of this function
Quote:

Originally Posted by arsenal12345
what about the question below that ?

You're welcome ><
• Sep 20th 2012, 01:52 AM
arsenal12345
Re: find the derivative of this function
Quote:

Originally Posted by Prove It
You're welcome ><

sorry please accept my apologies for my lack of manners :(