ok, it wants the normal line to a curve at a point is perpendicular to the tangent line at that point.
Find the equation of the normal line to this circle at Point A.
Find the equation of the normal line to this circle at Point B.
equation of the circle...
x^2 + y^2 = 25
PointA: (4,-3) PointB: (4,3)
equation of tangent line to A....4/3x-25/3
equation of tangent line to B....-4/3x+25/3
so it wants the perindicular normal line, so i figured it would be the same as the other, except the slope for A would be -3/4x, and B would be 3/4x, but it wasnt right....can you let me know whats wrong...thanks...
oh yeah...and this one...i dont really know where to start or how to go about doing it...some help...thanks...
Use the graph of f(x) and the tangent line shown below to answer the following.
(a) If k(x) = 1/ f(x), then
k '(2) =
(b) If g(x) = f -1(x), then
g '(5) =