Results 1 to 2 of 2

Math Help - integration

  1. #1
    Junior Member
    Joined
    Jul 2012
    From
    auckland
    Posts
    46

    integration

    how do i do this ? please show me with proper working
    y= ln(ln(tan x))




    also i did the one below , is it right ?

    ∫ sin y/cos^2 y= - cos y /cos^2 y= 1/cosy= sec y +c



    thank you
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,717
    Thanks
    634

    Re: integration

    Hello, arsenal12345!

    How do I do this? . y\:=\: \ln\left[\ln(\tan x)\right] . Do what?

    I see no way to integrate it.
    Do you want its derivative?




    Also I did the one below ... is it right ?

    . . \int\frac{\sin y}{\cos^2\!y}\,dy \:=\:\underbrace{-\frac{\cos y}{\cos^2\!y}}_{{\color{red}??}} \:=\:\frac{1}{\cos y} \:=\:\sec y + C

    \int\frac{\sin y}{\cos^2\!y}\,dy \;=\;\int\frac{1}{\cos y}\cdot\frac{\sin y}{\cos y}\,dy \;=\;\int\sec y\tan y\,dy \;=\;\sec y + C
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: November 3rd 2010, 12:54 AM
  2. Replies: 2
    Last Post: November 2nd 2010, 04:57 AM
  3. Replies: 8
    Last Post: September 2nd 2010, 12:27 PM
  4. Replies: 2
    Last Post: February 19th 2010, 10:55 AM
  5. Replies: 6
    Last Post: May 25th 2009, 06:58 AM

Search Tags


/mathhelpforum @mathhelpforum