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Math Help - Differentiate the given function y=√2x

  1. #1
    Junior Member arcticreaver's Avatar
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    Differentiate the given function y=√2x

    i'm having trouble doing the following problem - Differentiate the given function y=√2x.

    can anyone help with this?
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  2. #2
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    Re: Differentiate the given function y=√2x

    assuming you mean ...

    y = \sqrt{2x} = (2x)^{1/2}

    ... now use the chain rule.
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  3. #3
    Junior Member arcticreaver's Avatar
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    Re: Differentiate the given function y=√2x

    my book gives me the answer dy/dx =√2/2√x

    if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right?
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    Re: Differentiate the given function y=√2x

    Quote Originally Posted by arcticreaver View Post
    my book gives me the answer dy/dx =√2/2√x
    if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right?
    If y=\sqrt{f(x)} then y^{\prime}=\frac{f^{\prime}(x)}{2\sqrt{f(x)}}.
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  5. #5
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    Re: Differentiate the given function y=√2x

    y = \sqrt{2x} = (2x)^{1/2}

    \frac{dy}{dx} = \frac{1}{2} (2x)^{-1/2} \cdot 2 = \frac{1}{\sqrt{2x}}
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