i'm having trouble doing the following problem - Differentiate the given function y=√2x. can anyone help with this?
Follow Math Help Forum on Facebook and Google+
assuming you mean ... $\displaystyle y = \sqrt{2x} = (2x)^{1/2}$ ... now use the chain rule.
my book gives me the answer dy/dx =√2/2√x if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right?
Originally Posted by arcticreaver my book gives me the answer dy/dx =√2/2√x if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right? If $\displaystyle y=\sqrt{f(x)}$ then $\displaystyle y^{\prime}=\frac{f^{\prime}(x)}{2\sqrt{f(x)}}$.
$\displaystyle y = \sqrt{2x} = (2x)^{1/2}$ $\displaystyle \frac{dy}{dx} = \frac{1}{2} (2x)^{-1/2} \cdot 2 = \frac{1}{\sqrt{2x}}$
View Tag Cloud