Differentiate the given function y=√2x

**arcticreaver** · September 16th 2012, 01:09 PM

i'm having trouble doing the following problem - Differentiate the given function y=√2x.

can anyone help with this?

**skeeter** · September 16th 2012, 01:11 PM

assuming you mean ...

$y = \sqrt{2x} = (2x)^{1/2}$

... now use the chain rule.

**arcticreaver** · September 16th 2012, 01:19 PM

my book gives me the answer dy/dx =√2/2√x

if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right?

**Plato** · September 16th 2012, 01:36 PM

Originally Posted by arcticreaver

my book gives me the answer dy/dx =√2/2√x
if i used the chain rule then i got something like 1/2 * 2x^-1/2 = 1x^-1/2 = 1/√x... right?

If $y=\sqrt{f(x)}$ then $y^{\prime}=\frac{f^{\prime}(x)}{2\sqrt{f(x)}}$ .

**skeeter** · September 16th 2012, 01:42 PM

$y = \sqrt{2x} = (2x)^{1/2}$

$\frac{dy}{dx} = \frac{1}{2} (2x)^{-1/2} \cdot 2 = \frac{1}{\sqrt{2x}}$

Thread: Differentiate the given function y=√2x