I have been stuck on this question for a while now. I need to find the slope of the tangent to the curve 5 over the square root of x (5/squarerootX)

Printable View

- Sep 16th 2012, 11:41 AMneontiger94finding the slope of a tangent line
I have been stuck on this question for a while now. I need to find the slope of the tangent to the curve 5 over the square root of x (5/squarerootX)

- Sep 16th 2012, 11:49 AMskeeterRe: finding the slope of a tangent line
start by rewriting $\displaystyle y = \frac{5}{\sqrt{x}}$ so that you may use the power rule for derivatives

$\displaystyle y = 5x^{-1/2}$

continue ... - Sep 16th 2012, 12:08 PMneontiger94Re: finding the slope of a tangent line
When I use the power rule I get (-5/2) (x^-3/2) if i did that right i am still going to have a radical so how will I find the slope?

I'm sorry for coming off as such an amateur, but calc is the bane of my existence - Sep 16th 2012, 12:36 PMPlatoRe: finding the slope of a tangent line
- Sep 16th 2012, 12:40 PMneontiger94Re: finding the slope of a tangent line
Thats what I thought the answer was, but maybe I didnt specify the question properly. The question reads Find the slope m of the tangent to the curve

y = 5/square root x

at the point where x = a > 0.

does this help at all, beacuse I think I'm supposed to find the exact slope using the derivative as a function - Sep 16th 2012, 12:47 PMPlatoRe: finding the slope of a tangent line
- Sep 16th 2012, 01:01 PMneontiger94Re: finding the slope of a tangent line
Okay thank you I should have used the power rule from the beginning