if f(x)=g^2(x) f'(3)=? We're doing differentiation now, but I don't know how to solve this.
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$\displaystyle g^2(x) = [g(x)]^2$ the inner function is $\displaystyle g(x)$ is other is $\displaystyle x^2$.
I don't understand....
Originally Posted by MiDude I don't understand.... Neither do we! You have not told us about $\displaystyle g(x)$! What is that function?
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