How would one differentiate $\displaystyle y=\frac{(x+3)(x-8)}{x}$ I tried: $\displaystyle y=x^{-1}(x^2-5x-24)=x-5-24x^{-1}$ which is diffentiated to $\displaystyle 1+24x^{-2}$ Is this right? Thanks for your time.
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Originally Posted by Mukilab How would one differentiate $\displaystyle y=\frac{(x+3)(x-8)}{x}$ I tried: $\displaystyle y=x^{-1}(x^2-5x-24)=x-5-24x^{-1}$ which is diffentiated to $\displaystyle 1+24x^{-2}$ Is this right? The work is correct.
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