So when I integrated them, I got
ln (u) -6ln(1+6u)-6ln(1/1+6u)
is this right? if it's right do i just subsitute the u back to the original value?
Let's back up a step, are you sure your partial fraction decomposition is correct?
Once you are sure you have the correct decomposition, when you integrate, make the limits of integration reflect the substitution and you won't need to back-substitute for the original variable.
My upper limit is 12 and lower limit is so i substituted them as (ln12-6ln(1+6(12))-6ln(1/1+6(12))-(ln7-6ln(1+6ln(7)-6ln(1/1+6(7)) and the answer I got is 0.539 (in 3 sig fig). What did i do wrong? I used the graphics calculator to check the answer of the original function and it is 97.1 ... What did i do wrong? did I jump a step?
so my final equation just before substituting u into my upper and lower limit is:
(ln lul -6ln l1+6ul +1/6 (1+6u)^-1 ) ? Then multiply the answer by 10.5984 which is the constant we brought out to the in front of the integral?