# Math Help - slope of the line

1. ## slope of the line

how the slope is possibly solved?

the slope of the line tangent to the curve x + y^2 = 1 at (0,1)

how does it look like?

anybody....?

2. ## Re: slope of the line

Take the given equation:

$x+y^2=1$

Implicitly differentiate with respect to x:

$1+2y\frac{dy}{dx}=0$

$\frac{dy}{dx}=-\frac{1}{2y}$

At $y=1$ we then have:

$\frac{dy}{dx}\left|_{y=1}=-\frac{1}{2}$

and this is the slope of the line tangent to the curve at the given point.

3. ## Re: slope of the line

thank you MarkFL2