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Math Help - slope of the line

  1. #1
    rcs
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    slope of the line

    how the slope is possibly solved?

    the slope of the line tangent to the curve x + y^2 = 1 at (0,1)

    how does it look like?

    anybody....?
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: slope of the line

    Take the given equation:

    x+y^2=1

    Implicitly differentiate with respect to x:

    1+2y\frac{dy}{dx}=0

    \frac{dy}{dx}=-\frac{1}{2y}

    At y=1 we then have:

    \frac{dy}{dx}\left|_{y=1}=-\frac{1}{2}

    and this is the slope of the line tangent to the curve at the given point.
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  3. #3
    rcs
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    Re: slope of the line

    thank you MarkFL2
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