# Math Help - Looking for help on reversing a limit?

1. ## Looking for help on reversing a limit?

I need help looking at this problem.

$\lim_{h\to0}\frac{sqrt(16+h){-4}}{h}$

I'm tasked with finding f(x) and some number, a. I think it's supposed to resemble $\frac{f(x)-f(a)}{x-a}$ but that's not leading me anywhere.

Isn't $sqrt(16)$ the f(x) in this case with 4 being a? I don't need the derivative, so I think I'm supposed to go backwards. I guess I'm hoping someone might be familiar with this type of problem and could toss me a tip. Thanks at any rate.

2. ## Re: Looking for help on reversing a limit?

Consider the alternative definition of the derivative which is

lim h-> 0 [f(x+h) - f(x)]/h = f'(x) (i.e. the derivative of f at the point x). From this what can you conclude?