Can't seem to solve this question:
Sketch the graph of ln(x-3), then, without evaluating the integral, prove that
3/2ln10 < Integral of lnlx-3l, upper limit = 8, lower limit = 5 < ln125
Sorry I can't type the inequalities out in proper form ><, and by lx-3l I mean the modulus/absolute value.
This question falls under the topic of 'area under curve by integration', so I know it has something to do with that, but I just can't figure it out.
This is the graph with y = ln(x-3), y = 3/2ln10 and y = ln124