f(x)={14, x<-3 {ax^{2}+b, -3<x<2 {18-x, x>2
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Originally Posted by hplitz f(x)={14, x<-3 {ax^{2}+b, -3<x<2 {18-x, x>2 Solve for $\displaystyle a~\&~b$ so that $\displaystyle {\lim _{x \to - {3^ + }}}f(x) = 14~\&~{\lim _{x \to {2^ - }}}f(x) = 16$.
I got the answer a=-2/5 and b=88/5 Does that seem right?
Originally Posted by hplitz I got the answer a=-2/5 and b=88/5 Does that seem right? Yes it does. At least a is correct.
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