Thread: Some help/input on Limit Comparison Series Ques.

Can anyone give me some input as to what I could compare this to. At first glance, maybe I could do a limit comparison test with
bn= , which would simplify to

Since n is the dominant term, would I compare it with the harmonic series of ??

Any feedback appreciated. Thanks.

Anyone? I have no idea how to break down [n ln(n)] to find a suitable comparison.

ln(n) is larger than 1 for all n> 1 so that " ".

Originally Posted by HallsofIvy

ln(n) is larger than 1 for all n> 1 so that " ".

If you replace ln(n) by 1, then the series diverges. On the other hand, converges by the integral test.

Thanks for the responses, the problem make much more sense now.

Originally Posted by Beevo

Well I will the you that we do know that does converge.

But I am unsure of the comparison limit.