Okay, I was looking at this forever last night, and finally gave up. Today, I went to the math lab (basically math tutoring) to ask those guys to do it. As soon as I point to the problem in my book, the answer just comes to me >.<
I've attached a graph to illustrate this (I would have figured it out from the graph last night, but my problem was to integrate x+(1-x^2)^.5 so the graph looked different, and I didn't realize what I really had)
So, to save others the same frustration I had:
Set the function being integrated as equal to y
Realize that y must be positive, because no real number squared will give you a negative number.
Square the function
Add x^2 to both sides
Now realize that this is the equation of a circle. And because y must be positive, it is the equation for the top half of a circle.
Now we are trying to find the area from 0 to 1 under the top half of a circle, and who's center is the origin. Because the center is the origin, we know the area is only what is inside of the circle (ie if it were raised 1 unit, we would have to account for the additional area, but in this case we do not). And because it is the top half of the circle with radius 1 from 0 to 1, then we are taking the right half of the top half of the circle, so just a quarter of the circle who's radius is 1.
Area of a circle is and r = 1, so the area of our circle is . And since a quarter of the circle will have a quarter of the area, we can simply take a quarter of the total area.
Since integrals calculate the area under the graph of a function, from a to b, we are trying to find the area under and since is that area, then must be the solution to the integral.
Image attached to illustrate:
and in general, , where , represents the upper and lower halves, respectively, of the circle with center and radius .
What would be something like: ?
and the 4 means the radius will be 2
So the circle will span the domain of [0,4]
And since this is the upper half of a circle, then half of the total area is
On a side note, when you wrote the integral, you placed a tilde before "dx" I'm curious what this does/means.
It is just used to give a space. some users use \ or \, or \; but i find all of those unaesthetic. I want both my LaTex and my LaTex code aesthetic. Math is half about being elegant after all.On a side note, when you wrote the integral, you placed a tilde before "dx" I'm curious what this does/means.
without the ~:
with the ~:
you see how the dx is not stuck on the integrand? they give each other space
Aah, that makes sense. I don't like how it effects searches, though, makes it harder to search for things because you have to try various different ways of writing a function, and say someone already has solved the problem you're working on, but they wrote it a certain way, and you just can't find the right syntax to plug into the search feature, so you never find the thread. A trade off, I guess.
I think the site would really benefit from integrating the LaTeX into the search feature. Like a way to search through [tex] tags, and return places they had been used with links to the actual posts. Because right now, it's only easy to search for story problems, because they usually use the same phrases word for word. But if you have just an equation and are told to "differentiate" or "integrate" and you go to search for it, you have to hit the syntax just right to find the answer, and frequently instructors will change constants in order to reuse the same problem, so your answer might be out there, but you never find it because you are looking for instead of .
Anyway, it would be helpful because it would reduce redundant problems, and allow users to capitalize off of the previously answered questions.
a feature that can recognize that both these codes are saying the same thing would have to have A.I. or something