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Thread: Ack - Simple Question (y')

  1. #1
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    Ack - Simple Question (y')

    I just have a real quick simple question..

    I'm doing Implicit Differentiation, and I've had a mind slip.

    What's the derivative of 4yx implicitly?

    I know poroduct rule = 4y(1) + x(I forgot the derivative of 4y!)

    So basically...what's the derivative of 4y?
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  2. #2
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    Quote Originally Posted by Super Mallow View Post
    I
    What's the derivative of 4yx implicitly?
    That depends.

    If you desire to compute $\displaystyle y',$ then apply the product rule and apply the chain rule for $\displaystyle y.$ Otherwise, if you desire to compute $\displaystyle x'$ then apply the product rule and apply the chain rule for $\displaystyle x.$
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  3. #3
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    Quote Originally Posted by Super Mallow View Post
    I just have a real quick simple question..

    I'm doing Implicit Differentiation, and I've had a mind slip.

    What's the derivative of 4yx implicitly?

    I know poroduct rule = 4y(1) + x(I forgot the derivative of 4y!)

    So basically...what's the derivative of 4y?
    Differentiating with respect to x?

    d/dx 4yx = 4[y*1(dx/dx) +x*1(dy/dx)] = 4[y(1) +x(dy/dx)] = 4y +4x(dy/dx)
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  4. #4
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    Thanks for the help...I ended up getting it
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