How would you determine the degree of the Maclaurin polynomial required for the error in the approximation to be less than 0.0001 for
f(x)=cos(pi*x^2) approximating f(0.6)? Thanks!
Look at the form of the remainder of the Maclaurin polynomial. Set if to beOriginally Posted by Filthypeasant
less than 0.0001 then solve to find the minimum degree that satisfies
the inequality. This may need to be done by trial and error.
And it looks to me as though the required degree is 16.
Look at the post on Taylor polynomials just below this one for more details.
RonL