How would you determine the degree of the Maclaurin polynomial required for the error in the approximation to be less than 0.0001 for

f(x)=cos(pi*x^2) approximating f(0.6)? Thanks!

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- February 26th 2006, 09:41 PMFilthypeasantMaclaurin Approximation
How would you determine the degree of the Maclaurin polynomial required for the error in the approximation to be less than 0.0001 for

f(x)=cos(pi*x^2) approximating f(0.6)? Thanks! - February 27th 2006, 01:18 AMCaptainBlackQuote:

Originally Posted by**Filthypeasant**

less than 0.0001 then solve to find the minimum degree that satisfies

the inequality. This may need to be done by trial and error.

And it looks to me as though the required degree is 16.

Look at the post on Taylor polynomials just below this one for more details.

RonL