Well, this should be simpler than my previous posts =P
I need to find the derivative of this: Sin SqreRoot 2x
I use the chain rule, first to get this: Sin ((2x^1/2)) = Cos ((2x^1/2))
Then, I took the inside.
2x^1/2 = 1/2(2x)^/1/2 = X^/1/2
So, I ended up with Cos(SqreRoot2x) x 1/SqreRootX. I thought it was right, but the book is telling me the denominator is SqreRoot2x. I don't know where I went wrong.
Any help is appreciated!