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Thread: What is the Maclaurin series of 1/(x+1)^0.5?

  1. September 9th 2012, 08:25 AM #1
    TriKri
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    What is the Maclaurin series of 1/(x+1)^0.5?

    Does anyone know what the Maclaurin series of 1/\sqrt{x+1} is?
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  2. September 9th 2012, 08:58 AM #2
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    Re: What is the Maclaurin series of 1/(x+1)^0.5?

    Quote Originally Posted by TriKri View Post
    Does anyone know what the Maclaurin series of 1/\sqrt{x+1} is?
    Use Newton's Generalised Binomial Series with \displaystyle \begin{align*} (1 + x)^{-\frac{1}{2}} \end{align*}.
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  3. September 9th 2012, 11:21 AM #3
    TriKri
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    Re: What is the Maclaurin series of 1/(x+1)^0.5?

    Thanks!!
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  4. September 9th 2012, 11:45 AM #4
    TriKri
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    Re: What is the Maclaurin series of 1/(x+1)^0.5?

    I just found a way to generalize back and forth error compensation and correction
    Last edited by TriKri; September 9th 2012 at 11:47 AM.
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