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Math Help - integrating a sin function

  1. #1
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    integrating a sin function

    heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start
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    Re: integrating a sin function

    Quote Originally Posted by lolo6456 View Post
    heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start
    10.09x - \cos{x} + C
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    Re: integrating a sin function

    Quote Originally Posted by skeeter View Post
    10.09x - \cos{x} + C
    im only a high school student and sorry my function was actually (10.09+sin(x))^2
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    Re: integrating a sin function

    (10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}

    \int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =

    \int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =

    using the power reduction identity for \sin^2{x} ...

    \int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx

    can you finish?
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    Re: integrating a sin function

    Quote Originally Posted by skeeter View Post
    (10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}

    \int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =

    \int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =

    no :/ can u show me an example pls i have exercises like this to complete and i would like an example to follow so i can do my remaining questions

    using the power reduction identity for \sin^2{x} ...

    \int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx

    can you finish?
    i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.
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    Re: integrating a sin function

    Quote Originally Posted by lolo6456 View Post
    i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.
    show what you tried ...
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    Re: integrating a sin function

    Quote Originally Posted by skeeter View Post
    show what you tried ...
    i started from where u left of ins(integration sign)

    -20.18cos(x)+10.09dx+ins(1/2-1/2cos(2x)dx
    -20.18cos(x)+ins1/2dx+ins10.09dx-1/2inscos(2x) dx

    im stuckk what do i do nxt?
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  8. #8
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    Re: integrating a sin function

    \int 10.09^2 + 20.18\cos{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx =

    \int 10.09^2 \, dx + \int 20.18\cos{x} \, dx + \frac{1}{2} \int 1 \, dx - \frac{1}{2} \int \cos(2x) \, dx

    what is the antiderivative of the constant 10.09^2 ?

    what is the antiderivative of 20.18\cos{x} ?

    what is the antiderivative of the constant 1 ?

    what is the antiderivative of \cos(2x) ?
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    Re: integrating a sin function

    did i do it wrong?? this is confusingg sorry im just a bit slow when it comes to learning new things

    -1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?
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  10. #10
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    Re: integrating a sin function

    Quote Originally Posted by lolo6456 View Post
    -1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?
    what you posted makes no sense.

    you require more assistance than can be provided in this venue ... I recommend you consult your instructor.
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    Re: integrating a sin function

    ohh ok well thanks for helping any but what i did before am i on the right track??
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  12. #12
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    Re: integrating a sin function

    no
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  13. #13
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    Re: integrating a sin function

    anyway* cant u help by providing me with an example or u cant?
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  14. #14
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    Re: integrating a sin function

    I already asked you specific questions regarding antiderivatives in post #8 ... can you answer them?
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  15. #15
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    Re: integrating a sin function

    what is the antiderivative of the constant 10.09^2
    101.808x+c

    what is the antiderivative of 1 ?
    x

    not so sure about the other 2
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