1. integrating a sin function

heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start

2. Re: integrating a sin function

Originally Posted by lolo6456
heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start
$10.09x - \cos{x} + C$

3. Re: integrating a sin function

Originally Posted by skeeter
$10.09x - \cos{x} + C$
im only a high school student and sorry my function was actually (10.09+sin(x))^2

4. Re: integrating a sin function

$(10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}$

$\int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =$

$\int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =$

using the power reduction identity for $\sin^2{x}$ ...

$\int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx$

can you finish?

5. Re: integrating a sin function

Originally Posted by skeeter
$(10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}$

$\int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =$

$\int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =$

no :/ can u show me an example pls i have exercises like this to complete and i would like an example to follow so i can do my remaining questions

using the power reduction identity for $\sin^2{x}$ ...

$\int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx$

can you finish?
i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.

6. Re: integrating a sin function

Originally Posted by lolo6456
i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.
show what you tried ...

7. Re: integrating a sin function

Originally Posted by skeeter
show what you tried ...
i started from where u left of ins(integration sign)

-20.18cos(x)+10.09dx+ins(1/2-1/2cos(2x)dx
-20.18cos(x)+ins1/2dx+ins10.09dx-1/2inscos(2x) dx

im stuckk what do i do nxt?

8. Re: integrating a sin function

$\int 10.09^2 + 20.18\cos{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx =$

$\int 10.09^2 \, dx + \int 20.18\cos{x} \, dx + \frac{1}{2} \int 1 \, dx - \frac{1}{2} \int \cos(2x) \, dx$

what is the antiderivative of the constant $10.09^2$ ?

what is the antiderivative of $20.18\cos{x}$ ?

what is the antiderivative of the constant $1$ ?

what is the antiderivative of $\cos(2x)$ ?

9. Re: integrating a sin function

did i do it wrong?? this is confusingg sorry im just a bit slow when it comes to learning new things

-1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?

10. Re: integrating a sin function

Originally Posted by lolo6456
-1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?
what you posted makes no sense.

you require more assistance than can be provided in this venue ... I recommend you consult your instructor.

11. Re: integrating a sin function

ohh ok well thanks for helping any but what i did before am i on the right track??

no

13. Re: integrating a sin function

anyway* cant u help by providing me with an example or u cant?

15. Re: integrating a sin function

what is the antiderivative of the constant 10.09^2
101.808x+c

what is the antiderivative of 1 ?
x

not so sure about the other 2

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