# integrating a sin function

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• Sep 9th 2012, 04:40 AM
lolo6456
integrating a sin function
heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start
• Sep 9th 2012, 04:59 AM
skeeter
Re: integrating a sin function
Quote:

Originally Posted by lolo6456
heyy my sin function is 10.09+sin(x) and i was wondering how u would integrate it pls help i have no idea where to start

$\displaystyle 10.09x - \cos{x} + C$
• Sep 9th 2012, 05:06 AM
lolo6456
Re: integrating a sin function
Quote:

Originally Posted by skeeter
$\displaystyle 10.09x - \cos{x} + C$

im only a high school student and sorry my function was actually (10.09+sin(x))^2
• Sep 9th 2012, 05:20 AM
skeeter
Re: integrating a sin function
$\displaystyle (10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}$

$\displaystyle \int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =$

$\displaystyle \int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =$

using the power reduction identity for $\displaystyle \sin^2{x}$ ...

$\displaystyle \int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx$

can you finish?
• Sep 9th 2012, 05:35 AM
lolo6456
Re: integrating a sin function
Quote:

Originally Posted by skeeter
$\displaystyle (10.09+\sin{x})^2 = 10.09^2 + 20.18\sin{x} + \sin^2{x}$

$\displaystyle \int 10.09^2 + 20.18\sin{x} + \sin^2{x} \, dx =$

$\displaystyle \int 10.09^2 + 20.18\sin{x} \, dx + \int \sin^2{x} \, dx =$

no :/ can u show me an example pls i have exercises like this to complete and i would like an example to follow so i can do my remaining questions

using the power reduction identity for $\displaystyle \sin^2{x}$ ...

$\displaystyle \int 10.09^2 + 20.18\sin{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx$

can you finish?

i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.
• Sep 9th 2012, 05:50 AM
skeeter
Re: integrating a sin function
Quote:

Originally Posted by lolo6456
i tried but i cant seem to get answer could u show me pls? i have similar questions for in my workbook and i would like to complete them with an example to follow.

show what you tried ...
• Sep 9th 2012, 05:57 AM
lolo6456
Re: integrating a sin function
Quote:

Originally Posted by skeeter
show what you tried ...

i started from where u left of ins(integration sign)

-20.18cos(x)+10.09dx+ins(1/2-1/2cos(2x)dx
-20.18cos(x)+ins1/2dx+ins10.09dx-1/2inscos(2x) dx

im stuckk what do i do nxt?
• Sep 9th 2012, 06:12 AM
skeeter
Re: integrating a sin function
$\displaystyle \int 10.09^2 + 20.18\cos{x} \, dx + \frac{1}{2} \int 1 - \cos(2x) \, dx =$

$\displaystyle \int 10.09^2 \, dx + \int 20.18\cos{x} \, dx + \frac{1}{2} \int 1 \, dx - \frac{1}{2} \int \cos(2x) \, dx$

what is the antiderivative of the constant $\displaystyle 10.09^2$ ?

what is the antiderivative of $\displaystyle 20.18\cos{x}$ ?

what is the antiderivative of the constant $\displaystyle 1$ ?

what is the antiderivative of $\displaystyle \cos(2x)$ ?
• Sep 9th 2012, 06:23 AM
lolo6456
Re: integrating a sin function
did i do it wrong?? this is confusingg sorry im just a bit slow when it comes to learning new things

-1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?
• Sep 9th 2012, 06:28 AM
skeeter
Re: integrating a sin function
Quote:

Originally Posted by lolo6456
-1/4 ∫〖cos2x 2-20.18cosx+∫〖1/2 dx+∫〖10.09〗^2 〗〗?

what you posted makes no sense.

you require more assistance than can be provided in this venue ... I recommend you consult your instructor.
• Sep 9th 2012, 06:29 AM
lolo6456
Re: integrating a sin function
ohh ok well thanks for helping any but what i did before am i on the right track??
• Sep 9th 2012, 06:30 AM
skeeter
Re: integrating a sin function
no
• Sep 9th 2012, 06:30 AM
lolo6456
Re: integrating a sin function
anyway* cant u help by providing me with an example or u cant?
• Sep 9th 2012, 06:36 AM
skeeter
Re: integrating a sin function