Re: integrating a sin function

well, you do know the antiderivative of a constant ... that's a start.

fyi ...

$\displaystyle \int \sin{x} \, dx = -\cos{x} + C$

$\displaystyle \int \cos{x} \, dx = \sin{x} + C$

... you should already know the two above if you learned the derivatives of sine and cosine.

and for any constant $\displaystyle k$ ...

$\displaystyle \int \sin(kx) \, dx = -\frac{1}{k}\cos(kx) + C$

$\displaystyle \int \cos(kx) \, dx = \frac{1}{k}\sin(kx) + C$

... and these two should make sense if you understand the chain rule for derivatives.

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Re: integrating a sin function

heyy i did it a bit differently to u but and i came up with the right answer.

does it still work?? Attachment 24758