1. ## Integrating with fractions

Hi

I'm trying to integrate the following and I just can't get it. Any help please?

Integrate $\displaystyle \frac{2}{3*x^{\frac{2}{3}}}$

^Can't see what is wrong with my latex, can anyone please correct it?

I get $\displaystyle \frac{2}{3}*x^{\frac{-2}{3}}$ which I then integrate to $\displaystyle x^{\frac{1}{3}}*\frac{3}{1}=3x^{\frac{1}{3}}$ Which isn't right. Where am I going wrong?

Similarly with $\displaystyle \frac{-x^{\frac{-3}{4}}}{4}$

I end up getting $\displaystyle \frac{-1}{4}*x^{\frac{3}{4}}*\frac{4}{3}=\frac{-x^{\frac{3}{4}}}{3}$

Help would be greatly appreciated, thank you.

2. ## Re: Integrating with fractions

ans 1 :: $\displaystyle 2 x^{1/3}$

ans 2 :: $\displaystyle x^{1/4}$

3. ## Re: Integrating with fractions

Originally Posted by MaxJasper
ans 1 :: $\displaystyle 2 x^{1/3}$

ans 2 :: $\displaystyle x^{1/4}$
Can you tell me how you got those please? I can only continue answering those questions if I know the method.

4. ## Re: Integrating with fractions

Integrate $$\frac{2}{3\cdot x^{\frac{2}{3}}}$$ gives $\displaystyle \frac{2}{3\cdot x^{\frac{2}{3}}}$

Note you were missing a final }

5. ## Re: Integrating with fractions

First remove the constant factors then integrate then include the constants.

6. ## Re: Integrating with fractions

Originally Posted by MaxJasper
ans 1 :: $\displaystyle 2 x^{1/3}$

ans 2 :: $\displaystyle x^{1/4}$
Wouldn't answer 2 be (-)x^1/4 rather than just x^1/4? Since you started off with a -x.