x-intercepts are where
the y-intercept is
stationary points are where
also, check your derivative. should be ...
Having some trouble with the following two questions, I have an answer but it doesn't make sense...
A function f is defined by the formula f (x) = (x-1)^2 (x+2)
(a) Find the coordinates of the points where the curve with the equation y = f(x) crosses the x - and y-axes.
(b) Find the stationary points of this curve y = f(x).
For the derivative of (a) I got 2x^2 - 3 but I didn't know how to get the points from that... Help is much appreciated!
Hello, smr101!
You seem to be lacking in much of the basics,
. . both in Calculus and Algebra.
Maybe a full solution (with baby steps) will jog your memory.
Given: .
(a) Find the coordinates of the points where the curve crosses the x - and y-axes.
You don't know how to find intercepts?
Let
. . The y-intercept is
Let
. . The x-intercepts are and
(b) Find the stationary points of this curve.
For the derivative of (a) I got 2x^2 - 3 .This is wrong.
but I didn't know how to get the points from that. .You don't?
. . . . . . . .