Ok, I don't know how to go about this one at all. Find dy/dx by implicit differentiation. e^(x/y) = 8x - y
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Originally Posted by kwivo Find dy/dx by implicit differentiation. e^(x/y) = 8x - y Find
I got dy/dx= ye^(x/y) + 8y^2/ xe^(x/y) + y^2 Is that right because the hw prog is telling me it's wrong. Maybe I didn't simplify it all the way yet?
Originally Posted by kwivo Ok, I don't know how to go about this one at all. Find dy/dx by implicit differentiation. e^(x/y) = 8x - y Originally Posted by Krizalid Find Originally Posted by kwivo I got dy/dx= ye^(x/y) + 8y^2/ xe^(x/y) + y^2 Is that right because the hw prog is telling me it's wrong. Maybe I didn't simplify it all the way yet? So from Krizalid's post: (And you really need to use parenthesis!) -Dan
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