# Limit proof required for special case of chain rule

• Sep 4th 2012, 06:06 PM
lamp23
Limit proof required for special case of chain rule
I am trying to figure out how to prove the equality I circled below in red. I have figured out how to prove the text in blue but don't know how to use that to prove the equality I circled in red.
Below I will post the givens I'm trying to use and my guess of how to prove it.
P.S. I understand this only proves the chain rule in the special case where $\Delta u \neq 0$. This is from Stewart's Calculus and he does mention that this is not a full proof but I'm very curious how to prove this special case anyway.

http://i900.photobucket.com/albums/a...amp23/calc.jpg

I'm not sure if I'm using the right givens below.
In their blue form it looks like I will be able to use the transitive property of implication $(a \rightarrow b \wedge b \rightarrow c) \rightarrow (a \rightarrow c)$ if I can always let the $\epsilon$ from the 1st given equal the $\delta$ from the second line.
http://i900.photobucket.com/albums/a...3/deltau-2.jpg
• Sep 4th 2012, 07:15 PM
Prove It
Re: Limit proof required for special case of chain rule
• Sep 4th 2012, 09:52 PM
lamp23
Re: Limit proof required for special case of chain rule
I'm not looking for a way to prove the product of the limits is the limit of the product. I'm looking for a way to prove the two expressions I circled in red are equal, i.e. $\lim_{\Delta x\to 0}\frac{\Delta y}{\Delta x} = \lim_{\Delta u\to 0}\frac{\Delta y}{\Delta x}$