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Math Help - m having hard time solving this, i keep getting the same answer over and over

  1. #1
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    m having hard time solving this, i keep getting the same answer over and over

    the integral of sin^2 4θ dθ from -pi/4 to pi/4
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  2. #2
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    Re: m having hard time solving this, i keep getting the same answer over and over

    Did you try the identity

    \sin^2(x) = \frac{1 - \cos(2x)}{2}
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  3. #3
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    Re: m having hard time solving this, i keep getting the same answer over and over

    yes i did, and i got 0.785398 but my teacher says type your answer using pi
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    Re: m having hard time solving this, i keep getting the same answer over and over

    wer dealing with U sub.
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  5. #5
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    Re: m having hard time solving this, i keep getting the same answer over and over

    In this case, your teacher wants an exact answer. Solve the integral without using a calculator.
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  6. #6
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    Re: m having hard time solving this, i keep getting the same answer over and over

    this is my problem , because its definite integral and how am i get an exact answer ? im just to lost. so you mean i just U sub. without calculating the integral ?
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    Re: m having hard time solving this, i keep getting the same answer over and over

    There is a distinction between knowing the decimal expansion of a number, and its exact value. For example, your integral does have the value 0.785398, but that doesn't really mean anything mathematically, because its an approximation. The exact value in this case is actually \frac{{\pi}}{{4}}. You need to get the exact value.

    One way to do that is using the identity I copied above, and then use the anti-derivative with the fundamental theorem of calculus to find the definite integral. You can use u-substitution to find the anti derivative, but it can be done otherwise:

    \sin^2(4\theta) = \frac{1 - \cos(8\theta)}{2}

    So

    \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{1 - \cos(8\theta)}{2} d\theta = \frac{\theta}{2} - \frac{\sin(8\theta)}{16} evaluated from -Pi/4 to Pi/4

    = \frac{\pi}{8} - \frac{\sin(2\pi)}{16} - (-\frac{\pi}{8}) + \frac{\sin(2\pi)}{16} = \frac{{\pi}}{{4}}
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  8. #8
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    Re: m having hard time solving this, i keep getting the same answer over and over

    AHA !!! i got it now !! thanks my friend i really appreciate your help
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