Okay I'm trying to find this limit:
lim (ln(x))1/x as x approaches infinity using L'Hopital's rule.
This is what I've done so far:
y = (ln(x))1/x
ln(y) = (ln(ln(x)))/x
lim ln(y) = lim (ln(ln(x)))/x (Both as x approaches infinity)
(using L'H) = lim 1/(xln(x)) (as x approaches infinity)
That is what I have so far and I do not know where to go from there.
Also, sorry for the bad use of writing the equations and what not; I'm not sure how to write them on here as they should actually look, if that makes sense.